Answer Posted / rames

Here, 9 bits are required to get 500 hosts. Now, there will
be 7 bits available for the subnetting( i.e in the third
byte) so, we can create 254 subnets and 500 hosts per each
subnet with the given network ID (131.112.0.0)

Here, the subnet mask will be varying from
131.112.2.0/7 to 131.112.254.0/7 according to the no. of
bits we use for the subnetting in the third byte.

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