int *p=20;
if u print like dis printf("%d",p);
o\p:- 20; how is it possible?
plz give me the explanation.
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Answer Posted / saikishore
correct ans is
int *p ; // creating a pointer of integer type
*p=20; // we are creating memory for 20 and p is pointing to
it .
printf("%d",p); // prints p 's address
printf("%d",*p); // prints value pointed by p . i.e 20
wrong declarations
we
ERRORS 1.int *p=20;
| Is This Answer Correct ? | 4 Yes | 3 No |
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