Answer Posted / manojkumar challagundla
#include<stdio.h>
#include<conio.h>
void main()
{
int i,j;
int ctr=1;
for(i=1;i<=4;i++)
{
printf("\n")
for(j=1;j<=i;j++)
{
printf("%d",ctr);
ctr++;
}
}
}
| Is This Answer Correct ? | 2 Yes | 4 No |
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