Answer Posted / govind

step1) place one fileUpload control from tool box
step2) in it's Button click event
If FileUpload1.PostedFile Is Nothing Then
Response.Write("no file posted")

Else
Here Convert that image as byte and pass it
to function.
Dim con As SqlConnection
Dim cmd As SqlCommand
Dim ds As New DataSet

con = New
SqlConnection(ConfigurationManager.AppSettings("connectionString"))
cmd = New SqlCommand("insert into tablename
values(@image_in), con)
Dim imageByte(FileUpload1.PostedFile.InputStream.Length) As
Byte

FileUpload1.PostedFile.InputStream.Read(imageByte, 0,
imageByte.Length)
cmd.Parameters.AddWithValue("@image_in",
imageByte)
con.Open()
cmd.ExecuteNonQuery()
con.Close()

Response.Write("file is inserted")
End If

Explain about rapid application development tool?

518

---

Explain managed code?

536

---

Explain namespace?

574

---

Explain the advantages of vb.net?

529

---

What is a static class?

600

---

---

What is the main purpose of garbage collector?

511

---

Is vb.net a programming language?

540

---

how to get dynamic control array position or its index position?

2055

---

What is the difference between manifest and metadata?

552

---

Explain jit?

552

---

What are the differences between vb.net and c#, related to oops concepts

576

---

How do you call a stored procedure in Visual Basic?

587

---

Explain about the keyword must inherit?

583

---

What are nested classes?

542

---

Explain the difference between an xml "fragment" and an xml "document."

505

---