int *p=20;
if u print like dis printf("%d",p);
o\p:- 20; how is it possible?
plz give me the explanation.
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Answer Posted / valli
int *p=20;
means
int *p;
p=20;
so the address of p is 20
printf("%d",p);
it prints 20 because now the base address of p is 20
even if we print as
printf("%u",p);
the o/p will be 20
| Is This Answer Correct ? | 9 Yes | 2 No |
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