Answer Posted / mohd. karim

KVAR - Reactive Power
It's Present only in Inductive load, i.e. X-mer, Motor, X-
mission Line..etc

And This power is required for generating Magnetic field in
inductive load.

Here, i want to explain some formuls

KVA = Sqrt((kw)^2 + (Kvar)^2)
Where , KVA = Apparant Power
KW= Actual Power
Kvar= Reactive Power

PF=KW/Kva = KW/(KW+Kvar) = COS$

1. If the value of kvar is more. it means PF is Less.
2. If the value of Kvar is zero. It means Unity PF (PF=1).
it means Apparant Power is Maxi. and over KW Loading is
Maxi.

--> Practically PF is not Unity (PF=1). its near about One.

For Reducing Kvar Demand We install Capacitor In Ckt.

Dis-Advantage (If Kvar is More)

1. less KW Loading(Low load Allow) in system.
2.Power Factor will Poor.
3.High current in system so Conductor & Cable size increase.
4.Electricity bill will more (Money Loss)

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