Answer Posted / satya dev ( knight frank)
By PMMC type Ammeter
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Help need in transformer !? Hello Friends The parameters of 2300/230 v 50hz t/f is R1=0.286 ohm R`2=0.319 ohm Rc=240 ohm X1=0.73 ohm X`2=0.73 ohm Xm=49.2 ohm Secondary Load impedance ZL=0.387+J0.29 solve the exact equivalent circuit with normal voltage across primery.. I know every thing but i cant find CURRENT I1=? and I`2=? Please help me give solution or only Formula please please...
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FOR 16/20 MVA 132/33 KV ONAN/ONAF TYPE TRANSFORMER IT IS DESIGNED FOR 16 MVA WITH ONAN CONDITION.IT BECOMES 20 MVA UNDER ONAF CONDITION.LOAD LOSS IS GUARANTEED FOR 65KW AT 20 MVA AND % IMPEDANCE 13.75. PLEASE TELL US AT WHAT LOAD LOSS AND % IMPEDANCE IT SHOULD BE DESIGNED FOR 16 MVA AND WHAT WILL BE ITS EFFICIENCY AT 20 MVA?
