Answer / joshin

//program for selection sort
#include<stdio.h>
#include<conio.h>
#define MX 100
void selection(int [], int);
void selection(int a[],int n)
{
int minindx,t;
int i,j;
for(i=0;i<n-1;i++)
{
minindx=i;
for(j=i+1;i<n;j++)
{
if(a[j]<a[minindx])
minindx=j;
}
if(minindx!=i)
{
t=a[i];
a[i]=a[minindx];
a[minindx]=t;
}
}
}
void main()
{
int a[MX],i,n;
clrscr();
printf("enter total num of elements:");
scanf("%d",&n);
for(i=0;i<n;i++)
{
scanf("%d",&a[i]);
}
selection(a,n);
printf("sorted arrau:\n");
for(i=0;i<n;i++)
{
printf("%d \t",a[i]);
}
getch();
}

Answer / alam

#include<iostream>
using namespace std;
int main()
{
int i,t,j,min,n=0,m=0;
int a[6]={6,3,2,10,5,8};
//0 1 2 3 4 5
for(i=0;i<=13;i++)
{
m++;
min=i;
for(j=i+1;j<=5;j++)
{
if(a[j]<a[min])
min=j;
n++;
}
t=a[i];
a[i]=a[min];
a[min]=t;
}
cout<<"******Selection Sort*********"<<endl;
for(i=0;i<=5;i++)
{
cout<<"a["<<i<<"]="<<a[i]<<endl;
}

cout<<"Outer Loop Total count :"<<m<<endl;
cout<<"Inner Loop Total count :"<<n<<endl;


return 0;
}

Using string functions write a program that will accept the name of the capital as input value and will display the corresponding country. ------------------------ Capitals Countries ------------------------ Capitals Countries Ottawa Canada Moscow Russia Rome Italy I can't not get it to run properly

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How to reverse a linked list without using array & -1? Thank you.

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void main() { int i=7; printf("N= %*d",i,i); }

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Given an int variable n that has been initialized to a positive value and, in addition, int variables k and total that have already been declared, use a do...while loop to compute the sum of the cubes of the first n whole numbers, and store this value in total . Thus if n equals 4, your code should put 1*1*1 + 2*2*2 + 3*3*3 + 4*4*4 into total . Use no variables other than n , k , and total .

3 Answers  

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1 Answers  

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how tally is useful?

2 Answers  

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void main() { int i=1; printf("%d%d%d",i,++i,i++); } Cau u say the output....?

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2. A student studying Information Technology at Polytechnic of Namibia is examined by coursework and written examination. Both components of assessment carry a maximum of 50 marks. The following rules are used by examiners in order to pass or fail students. a. A student must score a total of 40% or more in order to pass (total = coursework marks + examination marks) b. A total mark of 39% is moderated to 40% c. Each component must be passed with a minimum mark of 20/50. If a student scores a total of 40% or more but does not achieve the minimum mark in either component he/she is given a technical fail of 39% (this mark is not moderated to 40%) d. Grades are awarded on marks that fall into the following categories. Mark 100-70 69-60 59-50 49-40 39-0 Grade A B C D E Write a program to input the marks for both components (coursework marks out of 50 and examination marks out of 50), out put the final mark and grade after any moderation. [30]

0 Answers  

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main() { char c; for(c='A';c<='Z';c++) getch(); }

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how to convert decimal to hexadecimal without using arrays just loops

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when i use cout or cin call & then either << or >> .....it shows declaration syntax error...what should i do? cout<<"anything"; int a; cin>>a; return 0;

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what is run time error?

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