How can we know the number of days between two given dates
using PHP?
How can we know the number of days between two given dates
using MySQL?
Answers were Sorted based on User's Feedback
Using PHP
$date1 = date("Y-m-d");
$date2= "2005-5-15";
$nodays = (strtotime()-strtotime())/(60*60*24);
echo "no of days are $nodays ";
Using mySql :
mysql>SELECT DATEDIFF(NOW(),'2005-5-15');
The output will give you the exact number of days.
Is This Answer Correct ? | 12 Yes | 4 No |
Answer / shaik abdul raheem
SELECT DATEDIFF('2006-04-01','2006-03-01')
Is This Answer Correct ? | 6 Yes | 0 No |
Answer / jitendra jhariya and sandeep s
function dateDiff($dformat, $endDate, $beginDate)
{
$date_parts1=explode($dformat, $beginDate);
$date_parts2=explode($dformat, $endDate);
$start_date=gregoriantojd($date_parts1[0], $date_parts1[1],
$date_parts1[2]);
$end_date=gregoriantojd($date_parts2[0], $date_parts2[1],
$date_parts2[2]);
return $end_date - $start_date;
}Now let us see how we use this function:$date1="07/11/2003";
$date2="09/04/2004";print "If we minus " . $date1 . " from "
. $date2 . " we get " . dateDiff("/", $date2, $date1) .
".";which generates If we minus 07/11/2003 from 09/04/2004
we get 421.
Is This Answer Correct ? | 6 Yes | 1 No |
Answer / vipul dalwala
php
-------------------------------------------------------
$noofdays = ceil(((strtotime($endDate) - strtotime
($startDate)) / (60*60*24)))
Mysql
-------------------------------------------------------
SELECT ((UNIX_TIMESTAMP('2007-10-01') - UNIX_TIMESTAMP
('2007-09-04'))/(60*60*24)) AS dateDiff;
Is This Answer Correct ? | 5 Yes | 4 No |
Answer / vinay sachan
<?PHP
// different between two dates by date_diff() function:-
$datetime1 = date_create('2010-01-01');
$datetime2 = date_create('2012-1-15');
$interval = date_diff($datetime1, $datetime2);
echo $interval->format('%a days')."<br>";
//+744 days
echo $interval->format('%y-%m-%d days')."<br>";
//2-0-14 days
// different between two dates by strtotime() function:-
$now = time(); // or your date as well
$your_date = strtotime("2010-01-01");
$datediff = $now - $your_date;
echo floor($datediff/(60*60*24)) ."<br>";
//744
?>
for more PHP questions and their best answers and PHP notes at http://onlinephpstudy.blogspot.com/
Is This Answer Correct ? | 1 Yes | 0 No |
Answer / indira majumder
<?php
$date1 = date('y-m-d');
$date2 = '2007-12-7';
$days = (strtotime($date2)-strtotime($date1))/(60*60*24);
echo "Number of Days since '2007-12-7': $days";
Is This Answer Correct ? | 0 Yes | 1 No |
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