ORA-13146: could not find table substitution variable string



ORA-13146: could not find table substitution variable string..

Answer / guest

Cause: The partition name substitution variable %s was not
found in the SQL filter.

Action: The substitution variable %s must be in the SQL
filter to indicate where that partition name should be placed.

Please add more information about this Error

Is This Answer Correct ?    0 Yes 1 No

Post New Answer

More Oracle Errors Interview Questions

RMAN-06729: no backup of the SPFILE found to restore

1 Answers  


ORA-29811: missing STATISTICS keyword

1 Answers  


ORA-39092: unable to set SCN metadata for object "string.string" of type string

1 Answers  


ORA-39005: inconsistent arguments

1 Answers  


ORA-28107: policy was disabled

1 Answers  






TNS-03601: Failed in route information collection

1 Answers  


EXP-00030: Unexpected End-Of-File encountered while reading input

1 Answers  


LFI-01502: Base filename does not exist.

1 Answers  


ORA-14603: [SUBPARTITIONS | SUBPARTITION TEMPLATE] subpartition_count syntax is valid only for range-hash tables

1 Answers  


ORA-27195: proxy copy not supported

1 Answers  


NNL-00259: Server-generated requests now require authoritative answers

1 Answers  


ORA-22313: cannot use two versions of the same type "string"

1 Answers  


Categories