find highest salary
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Answer / subashvns
SELECT DISTINCT (
s1.salary
)
FROM `salary` s1
WHERE n -1 = (
SELECT count( DISTINCT (
s2.salary
) )
FROM `salary` s2
WHERE s2.salary > s1.salary )
| Is This Answer Correct ? | 4 Yes | 3 No |
Answer / renji
SELECT DISTINCT (
s1.salary
)
FROM `salary` s1
WHERE n -1 = (
SELECT count( DISTINCT (
s2.salary
) )
FROM `salary` s2
WHERE s2.salary > s1.salary )
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / qadeer
SELECT DISTINCT (
s1.salary
)
FROM `salary` s1
WHERE n -1 = (
SELECT count( DISTINCT (
s2.salary
) )
FROM `salary` s2
WHERE s2.salary > s1.salary )
| Is This Answer Correct ? | 2 Yes | 2 No |
FOR Nth Highest Salary Where N= 1,2,3,4
SELECT * FROM EMP E1 WHERE N=(SELECT COUNT(DISTINCT SAL)
FROM EMP E2 WHERE E1.SAL <= E2.SAL)
I have tested This Query on MySQL 5.1.41. its working fine.
| Is This Answer Correct ? | 1 Yes | 1 No |
Answer / richa
$P = shell_exec("SELECT salary
FROM mytable
ORDER BY
salary DESC");
echo $p[0];
| Is This Answer Correct ? | 0 Yes | 2 No |
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