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You have one base class virtual function how will call that
function from derived class?
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Answer Posted / narendra
class A
{
public:
virtual void fun()
{
cout<<"class A\n";
}
};
class B:public A
{
public:
virtual void fun()
{
cout<<"class B\n";
A::fun(); //calling base class virtual function.
}
};
| Is This Answer Correct ? | 4 Yes | 2 No |
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class CTest { public: void someMethod() { int nCount = 0; cout << "This is some method --> " << nCount; } }; int main() { CTest *pctest; pctest->someMethod(); return 0; } It will executes the someMethod() and displays the value too. how is it possible with our creating memory for the class . i think iam not creating object for the class. Thanks in Advance... Prakash
