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why the current leads voltage in the case of a capasitor
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Answer Posted / amey
the equestion of capasitor=(q=cv)
or q=c*Vm sinwt.
now current is the rate of flow of charge.
therefore,dq/dt=c*Vm*w coswt.
i=c*Vm*w coswt.
Im sinwt=Vm/(1/wc)sin(wt-90)...........(1)
now from this equestion curent(Im) leads voltage(Vm) by
angle 90 degree.
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