Answer Posted / atreyee

char * const, the pointer is declared as constant.
const char *, the pointer is not constant.

Do class declarations end with a semicolon?

1061

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What are the advantages of c++? Explain

1050

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What is meant by forward referencing and when should it be used?

1002

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Is arr and &arr are same expression for an array?

1042

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What is the difference between method overloading and method overriding in c++?

1136

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When do we run a shell in the unix system?

1059

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What is constructor and destructor in c++?

1099

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What are exceptions c++?

1025

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What is set in c++?

1110

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What things would you remember while making an interface?

993

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What does 7/9*9 equal ? a) 1 b) 0.08642 c) 0

949

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an operation between an integer and real always yeilds a) integer result b) real result c) float result

1140

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How do you sort a sort function in c++ to sort in descending order?

981

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Is c++ faster than c?

1007

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how can i access a direct (absolute, not the offset) memory address? here is what i tried: wrote a program that ask's for an address from the user, creates a FAR pointer to that adress and shows it. then the user can increment/decrement the value in that address by pressing p(inc+) and m(dec-). NOW, i compiled that program and opened it twice (in 2 different windows) and gave twice the same address to it. now look what happen - if i change the value in one "window" of the program, it DOES NOT change in the other! even if they point to the same address in the memory! here is the code snippet: //------------------------------------------------------ #include //INCLUDE EVERY KNOWN HEADER FILE #include //FOR ANY CASE... #include #include #include main() { int far *ptr; //FAR POINTER!!! long address; char key=0; //A KEY FROM THE KEYBOARD int temp=0; clrscr(); cout<<"Enter Address:"; cin>>hex>>address; //GETS THE ADDRESS clrscr(); (long)ptr=address; temp=*ptr; //PUTS THE ADDRESS IN THE PTR cout<<"["<

2403

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