write the function. if all the character in string B appear in
string A, return true, otherwise return false.
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Answer Posted / tushar
using namespace std;
#include<iostream>
#include<conio.h>
#include<string.h>
int main()
{
char str1[10],str2[10],temp[10];
char *p,*q;
int flag=1;
cout<<"enter the two strings"<<endl;
cin>>str1;
cout<<"and"<<endl;
cin>>str2;
p=str1;
//strcpy(str2,temp);
//cout<<temp;
if(strlen(str1)!=strlen(str2))
flag=0;
while(*p)
{
char ch=*p;
q=str2;
while(*q)
{
if(ch!=*q)
q++;
else
{
*q='*';
break;
}
}
if((*q)=='\0')
{flag=0;
break;
}
p++;
}
if(flag)
cout<<"anagrams"<<endl;
else
cout<<"not anagrams"<<endl;
getch();
return 0;
}
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