Given an array of size N in which every number is between 1
and N, determine if there are any duplicates in it. You are
allowed to destroy the array if you like.
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Answer Posted / ashutosh k
You can use intermediate step for count sort.
Take a new array B of size N, initialize all values to 0.
and then
for each i from 1 to N,
if((++B[A[i]]) > 1) - there are duplicates.
--- Time complexity O(n)
| Is This Answer Correct ? | 29 Yes | 7 No |
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