If perfect numbers, except 6, can be expressed by the sum of the cubes of an unbroken sequence of consecutive odd integers, what are the consecutive odd integerswhich, when cubed, give the perfect number 28?
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Answer Posted / Vandana
The consecutive odd integers that, when cubed, give the perfect number 28 are 1 (cubed = 1) and 7 (cubed = 343), because 1 + 343 = 344 which is not a perfect number. However, 7^3 - 1^3 = 338, which when added to 2 (cubed = 8) gives the perfect number 338 + 8 = 346.
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