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Unsigned char c;
for ( c=0;c!=256;c++2)
printf("%d",c);
No. of times the loop is executed ?
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Answer Posted / sundeep
First of all the code returns compile time error....bcoz
of "c++2",and c!=256 becoz unsigned char takes just 255
bytes..........and exceeding that results in compile time
error........
| Is This Answer Correct ? | 6 Yes | 4 No |
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