What is the integral value of sec(square)x, with upper limit 180/4 and lower limit 0 ?
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Answer Posted / Kaushal Pratap Singh
"To calculate this integral, it would be necessary to use integration techniques such as substitution or trigonometric identities. However, here is a step-by-step approach to solve it: sec(square)x can be rewritten as (1/cos^2 x). Let's substitute u = cos(x), then du = -sin(x) dx. After the substitution, the integral becomes Integral[-sqrt(2) from 0 to sqrt(2)/2] of (1/u^2) du. This integral can be solved by parts and evaluates to ln|u+sqrt(u^2-1)| evaluated at u=sqrt(2)/2 and u=0."
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