A, B ans C are three speakers. They have to speak randomly along with another 5 speakers in a function. A has to speak before B and B has to speak before C. What is the probability.
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Answer Posted / Hina Mansoori
The total number of possible arrangements for all speakers is 8! (8 factorial) since there are 8 unique speakers. The number of arrangements where A speaks first, followed by B, then C, is 6! (6 factorial), as any arrangement with A-B-C can be moved to the beginning. So the probability is 6! / 8! = 5/28.
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