The SFC of an engine is 0.25 kg/kW hr. when the fuel used has a calorific value of 36000 kJ/kg. the thermal efficiency of the engine is
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Answer Posted / Raja Singh
Thermal Efficiency = (Work done by engine) / (Heat supplied to engine) = (Power x Time) / (Mass of fuel x Calorific Value) = (1 x 36000) / (0.25 x 36000) = 1
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