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Method of findingthe dry ingredient quantity of 1 m3
concrete.
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Answer Posted / munna kumar das
suppose concrete mix ratio=1:1.5:3
and dry material required for 1cum of concrete =1.54
Let 1x+1.5x+3x=1.54
x=0.28
cement=0.28*1=0.28cum=0.28*1440/50=8.06bags
sand=0.28*1.5=0.42cum=0.42*1500=630Kg
coarse agg=0.28*3=0.84cum=0.84*1550=1302kg
add 6 to 8% extra material.
This process very easy to understand.
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