Answer Posted / vikas p

Consider M20 (1:1.5:3) Grade Concrete

A) Suppose Total Volume of concrete= 1 Cum.
B) Add 55% volume for dry mortar=0.55 Cum.
C) Total wet volume of concrete A+B = 1.55 Cum.
D) Cement = 1.55/ (1+1.5+3) = 0.18 Cum. = (0.18/0.035=5.14 Bags)
E) Therefore Fine aggregate = 0.18 cum X 1.5 = 0.27 Cum.
F) Therefore Coarse aggregate = 0.18 cum X 3 = 0.54 Cum.

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