Answer Posted / buhari adam nuhu kaakamu

NOTE:
1 CuM of concrete
Avg. final mix (Decnce) (AFM) = 1.52
Total proportion (TP) 1+2+4 = 7
Unit weight of cement =1440 KG/CuM

Solution.
Cement quantity required = AFM/TP
= 1.52/7
= 0.217 CuM
Cement is measure by weight
So therefore you multiply 0.217 by unit weight of cement
Cement quantity = 0.217 * 1440 = 312.48 KG.
Number of Cement bags = 312.48 / 50
= 6.2496 bags

Sand quantity = TP * 2
= 0.217 * 2
= 0.434 CuM

Stone quantity = TP * 4
= 0.217 * 4
= 0.868 CuM

Quantity of materials

Cement Bags = 6.2496 Bags

Sand = 0.434 CuM

Stone = 0.868 CuM

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