how to calclate the cemment for 1 cubic metre of 1:2:4 concrete
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Answer Posted / dipak rakibe
TO DERIVE THE QUANTITY OF INGREADIENT MATERIAL FOR 1 CUBIC METER OF CONCRETE FOR M-15 GRADE
Proportion for M-15 Concrete is 1:2:4
For Easy Calculations Take/Assume 10 Cu. m. of concrete.
Proportion
10 X 1.52 = 15.2
(Here 1.52 is the dry volume factor)
A) Quantity of Cement =
For 10 cum of concrete
(1/ 1+2+4)= 0.143 X 15.2 = 2.17 Cum
1 Bag of Cement = 35 Liters = 0.035
Quantity of Cement Bags = 2.17/.035 = 62.10 Bags
for 1 cum of concrete = 6.21 Bags
B) Quantity of Fine Aggregates/Sand
For 10 cum of concrete
(2/ 1+2+4)=0.285 X 15.2=4.33 Cum
Quantity of Sand = 4.33 Cum
for 1 cum of concrete = 0.43 Cum
C) Quantity of Coarse Aggregates/ Gitti
For 10 cum of concrete
(4/ 1+2+4)= 0.571 X 15.2 = 8.68 Cum
Quantity of Gitti = 8.68 Cum
for 1 cum of concrete = 0.87 Cum
Summary =
A) Cement Bags= 6.210 Bags
B) Fine Agg./Sand=0.43 Cum
C) Coarse Agg./Gitti = 0.87 Cum
BY Dipak Rakibe
| Is This Answer Correct ? | 9 Yes | 1 No |
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