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How to calculate KW saving for power factor correction from
0.92 to 0.98 at 350KW load?
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Answer Posted / engr mimkhan
IF your system losses is 5 %
Then loss reduction =1- (squr(.92)/squr(.98))
=0.13
=0.13 x 0.05 (5%)
=0.0065
Thus saving in kw =0.0065 x 350
=2.27 kw
This is your saving if system losses increase than kw saving will also increase..
Note squr mean Squre not root.
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