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IF we have 500kva transformer & know the current on HT & LT side, how can we consider for its breaker?
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Answer Posted / maze one
S = I x V x sq. root of 3
where:
S = Apparent Power, VA
I = Current, A
V = Voltage, V
note : use sq. root of 3 if the system is 3 phase
let's say Voltage = 460V @ Secondary Side
I = (500,000 VA)/(460V)(sq. root of 3)
I = 1,882.66 A
you may multiply the safety factor by 125% to 250%
or using inversed time circuit breaker by 250%
I will use 125% only, that is safe
I = 1882.66 x 125%
I = 2,353.325 AT
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