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In 120 m high RCC Chimney shell construction how we can
calculate the inner and outer dia of shell at every +1 m
level as this shell is inclined from bottom to top.
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Answer Posted / omkar
example:
bottom outer dia=100mt top outer dia =82mt height=120mt wall
thickness=0.5mt
(100-82)/120=0.15mt each 1mt reduce the dia 0.15mt ok
+4m outer dia=(100-(4*.15))=99.40mt dia
+4m inner dia=(99.40-2*0.5(wall thickness)=98.40mt dia
chimney 90degree maintain =center point maintain 0 to 120mt&
check radius every +1mt
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