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The matrix of a (7,9)was given.The address of the first byte
of a (1,1)matrix=1258.It takes 4 bytes to store the
number,then calculate the address of the last byte of a
(5,8) matrix??
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Answer Posted / rohit
to find starting byte for matrix a(5,1):
1258+(4*(9*4))-(1)=1401
then to find last byte for matrix a(5,8):
1401+(8*4)=1433
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f(X)-f(X-1)=f(X-8) FOR X>5 THEN X=
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