Answer Posted / bharath m,+91 8438238335/99806

2 Under-reamed cast in situ pile of 300 mm dia. of 10.00 m
length.
Solution :
(Pls. refer construction practice book & IS 2911 Part-III.)
2 under reamed pile means there are 2 Nos. of bulbs at particular spacing based on friction of soil.

Dia. of pile : 0.30 m. ie.,bulb dia. = 2.5 times dia. of pile
So it is 2.5*.3 = .75 m.
Length of Pile = 10.00 m.
Bulb thickness at pile intersection end (30-45degree inclination)= 1.75 times pile dia.
=1.75*.3
=0.525 m. &
free end = dia. of pile/4
=.3/4
=0.075 m.
Now follow the calculation:
Step 1:
Pile volume = Area x length
3.14/4*dxd x length
=3.14/4*.3*.3*10 = 0.707 Cubic Metre. ------1

Extra for Bulb Volume = Perimeter x Depth of bulb
=2*3.14*r x db
r at centre line of bulb = ((.75-.3)/2)+.3 = 0.525 m.
V=2*3.14x .525x(.525+.075)/2
=0.989 Cum. for 1 Bulb
V for 2 Bulb = .989*2
=1.978 Cubic metre -----2

Now combined Total Volume of Concrete 1+2 = .707+1.978 = 2.685 Cubic Metre.

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