Answer Posted / kungan kumar
weight of bar = (dia of bar)^2/162 kg
in feet = ans/3.28
1m. = 3.28ft
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My daily concrete volume of M25 concrete is 1st day= 25 Cum 2nd Day = 45 Cum 3rd Day = 55 Cum 4th Day = 22 Cum 5th Day =72 Cum 7th Day = 49 Cum. What will be acceptance criteria of concrete considering as per is 456 cl.15 and table 11 (cl 16.1 and 16.3).
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