Compiler will convert variable b to unsigned int b and then do the addition

look at following code

void foo(void) {
unsigned int a = 6;
int b = -20;
int c = (a+b > 6) ? 1:0;
}
o/p is 1 why
explain promotion rules

Question Posted / nitin sharma

Answer Posted / nitin sharma

Compiler will convert variable b to unsigned int b and then do the addition. Which will be greater than 6 and you got 1.

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