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how do we calculate quantity of cement , sand and
aggregates in 1 m3 of M30 grade concrete ?
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Answer Posted / kavinder
For M30 nominal mix, considering the ratio (1:1:2),
Cement = 1
Fine Agg = 1
Coarse Agg = 2
Total = 1+1+2=4
Considering the above ratio in grams i.e, (cement = 1 gm, Fine agg = 1 gm, Coarse agg = 2 gm) then
For 1 cum, 1/4 = 0.25 % will be filled.
Now, Volume of 1 bag of cement is 35 litres or 0.035 mL
Since, to maintain W/C ratio, the amount of cement & water should be equal.
Therefore, 1 gm of cement will require 0.035 mL of water.
0.25/0.035 = 7.15 approx. Bags or 357.5 kg of Cement.
or consider like this
1/((1+1+2)*0.035) = 7.15 approx. Bags or 357.5 kg of Cement (7.15 * 50 = 357.5), here ratio is 1 therefore 1*50=50
Fine Agg = 357.5 kg (7.15 * 50 = 357.5), here ratio is also 1 therefore 1*50=50
Coarse Agg = 715 kg (7.15 * 100 = 715), here ratio is 2 therefore 2*50=100
Adding all, 357.5+357.5+715 = 1430 kg
| Is This Answer Correct ? | 2 Yes | 6 No |
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