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If the load is 10Kw and power factor has to improve from 0.5
to 0.8,how can we select the capacitor rating
accordingly.Illustrate by showing formula?
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Answer Posted / ahatesham
at 0.5pf Apparent power is 10/0.5=20VA
reactive power = 17.321kVAR.
At 0.8pf
APPARENT POWER =10/0.8=12.5VA
Reactive power=7.5kVAR
So we need to provide (17.321-7.5)=9.821kVAR reactive power
through capacitor to bring of up 0.8 from 0.5.
So we need a capacitor rated for approximately 10kVAR to
achieve the target.
ANS= CAPACITOR RATING 9.821kVAR (approximately 10 kVAR)
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