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int main()
{
int *p=new int;
*p=10;
del p;
cout<<*p;
*p= 60;
cout<<*p;
}
what will be the output & why?
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Answer Posted / jaroosh
There will be an error because its "del" instead of "delete".
In this particular program, you might actually get away with
using p after delete, but lets look what happens here :
int *p=new int;
*p=10;
cout << "ADDRESS OF P is " << p << endl;
delete p;
int * x= new int(3);
cout << "ADDRESS OF X=" << *x << " is " << x << endl;
*p = 10; //We think we got away with deleting p so why not
//still use it!
cout << "VALUE OF X : " << *x; //Here is why...
now, though its basically a policy of compiler, here is what
probably WILL happen in the output (memory addresses are
exemplary):
ADDRESS OF P is 0x272740
ADDRESS OF X=3 is 0x272740
VALUE OF X : 10
Now this is totally NOT what we would like our program to
do, and this is because though delete WILL mostly call
objects destructors and sometimes even clear memory, but p
is STILL pointing to that location, to which compiler
assumes it is safe to allocate variable x!
So now we end up having ONE memory storage and two pointers
p and x pointing to it.
This is why though it will not crash your compilation and
probably you can get away with no runtime errors, this leads
to serious troubles and as a rule NEVER use pointers after
you deleted their storage.
| Is This Answer Correct ? | 7 Yes | 1 No |
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