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Father is aged three times more than his son Ronit. After 8
years, he would be two and a half times of Ronit's age.
After further 8 years, how many times would he be of Ronit's
age?
A.2 times
B.2 1/2times
C.2 3/4times
D.3 times
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Answer Posted / ans
let ronit's present age be x
the father's age will be =x+3x=4x
after 8 years-4x+8=5/2(x+8)
3x=24
x=8
therefpre,required ratio is 4x+16/x+16= 48/2=2
so option A is correct!
| Is This Answer Correct ? | 13 Yes | 6 No |
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