void main()
{
for(int i=0;i<5;i++);
printf("%d",i);
}

What is the output?..

Answer Posted / ramveer

for the first loop i is 0 so 0 is printed
for 2nd time i++ i becomes 1 so 1 is printed
for 3rd time i becomes 2 so 2 gets printed
for 4th time i becomes 3 so it gets prited
for 5th time i becomes 4 so it gets printed
now for this time i has became 5 and this isn't in loop boudary as the condition is i<5 so its breaks out of loop.

so the ans is "0 1 2 3 4" .

Is This Answer Correct ?    9 Yes 10 No



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