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WAP find square root of any number (without using sqrt() )?

Answer Posted / bhavya b

square of a no: n is the sum of first n odd no: for eg ..square of 7 is 1+3+5+7+9+11+13=49...
so we can find sqrt(m) by decrementing odd no:s from m upto m become 0 or less..then the no: of odd no:'s decremented will give the sqrt(m).

int sqroot(int m){
int n=0,i=1;
while(m>0){
m=m-i;
i+=2;
n++;
}
return(n);
}

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