If we have 15000kw connected load in a factory than how much
power demand sanction should be taken from electricity board.
Pls provide complete calculation.
- 3 Answers
- 6556 Views
- I also Faced
- E-Mail Answers
Answer Posted / rakesh maharjan
Remember the formula
KW=1.732 x V xI x PF
or
KW= KVA x PF, where PF = 0.8
connected load KW= Full load kw x 80%
Here in your case, connected load KW= 15000kw
so full load KW= 15000/80%=18750 KW
KVA= KW/.8
KVA=18750/.8=23437 KVA, this is the demand sanction.
I am junior Engineer.
Please verify by senior designer also.
| Is This Answer Correct ? | 5 Yes | 3 No |
Post New Answer View All Answers
DESCRIBEPNEUMATIC SYSTM OF ASH HANDLING PLANT
What is the different between digital phase converter and ordinary phase converter?
What is difference between safe PLC and normal PLC
please give me all the Alarm .Trip ,Safety Relays & Conditions of UPS Systems mail me on ashokbabunhce@gmail.com
A 1F capacitor is charged to 100V initially. A 1H inductor is connected accros the capacitor througha a switch. The current in the circiut when the switch is closed is____
reason of diode failure in alternator
Why is a synchronous motor always star connected??
What is a dominant pole?
What is shunt voltage and u v voltage witch one best
what purose of the double circuit transmission line phase of the line phase changed for circuit-1 for Circuit-2 R-Y-B B-Y-R
Can clean earth cable be considered as low current cable
what is meant by skew width in machines?
i want to know how to determine that a surge arrester work properly in 11kv system. and how to test a 12kv surge arrester
What are the significant parts of dc generator?
what will be the maximum winding temperature of 6.6kv HT motor 450kw, Full load current 49A. 50Hz Frequency.
