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In how many iterations can we find one coin that is heavier
than the others out of 8 coins?and how ?please reply
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Answer Posted / wareagle
Answer 1 is incorrect. Suppose the heavy coin is in the
first two coins you removed from the stack of 8.
1. Divide the coins into 2 groups of 4 and weigh each stack.
one stack will be heavier. 2.Take the heavier stack of 4
coins and divide into 2 stacks of 2 coins each. Weigh the 2
stacks. 3.One will be heavier. Take the 2 coins left and
weigh them. Take out the heavier of the 2 coins.
| Is This Answer Correct ? | 10 Yes | 9 No |
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