1) You have 8 coins. 3 of them weigh x units, 3 y
units, 1 a units and 1 b units. They are all mixed and look
identical. You have to find the lightest coin in minimum
number of weighing .
Answer Posted / pratik taank
Hi Dinesh,
This is regarding ur above answer.
i think u are wrong.
Step-1 is ok.
Step-2 is not - Plz see explanation below.
When in step-2 u divide 4 coins in 2 pairs, it is not necessary that lighter coin will be on the lighter side, it can be on a heavier side for ex -
there r 4 coins, their wts are 2gm, 8gm, 3gm, 4gm
put them in balance- 2gm and 8gm on 1 side
3gm and 4gm on other side.
now the lighter coins is in heavier side, now u have ignored this logic. try something new buddy!!!
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