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1) You have 8 coins. 3 of them weigh x units, 3 y
units, 1 a units and 1 b units. They are all mixed and look
identical. You have to find the lightest coin in minimum
number of weighing .

Answer Posted / dinesh thouna

as there are 8 coins..put 4 on one side and the other remaining 4 on the other side.. obviously one side will be lighter..
now the possible combinations of coins which can be on the lighter side are:
1)x,x,,x,a 2)x,x,x,b 3)x,x,x,y 4)x,x,y,y 5)3)x,x,y,a 4)x,x,y,b 5)x,x,a,b 6)x,y,a,b 7)x,y,y,a 8)x,y,y,b 9)x,y,y,y 10)y,y,y,a 11)y,y,y,b 12)y,y,a,b

well whatever the combination be, you need to divide it again into a group of 2-2..you will again get a lighter group..finally compare the last two coin and u will get the lightest coin of the 8 coins given...
so, that makes a total of 3 steps..
thumbs up..!! :)
# refer the above possibilities to get a clearer picture

Is This Answer Correct ?    2 Yes 5 No



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