Answer Posted / peter shonfield

Answer depends on temperature and can be calculated based on the ideal gas law. PV=nRT
P=pressure (atmospheres)
V=volume (litres)
n=moles of gas
T=temperature (K)
R=gas constant = 0.08206

Therefore at 25 deg C (298K) the volume occupied by 1 mole of oxygen= nRT/P = 1*0.08206*298/1 = 24.45 litres

Oxygen has a molecular mass of 32 g

Therefore mass of 1 m3 oxygen = 32/24.45*1000 = 1309 g = 1.309 kg

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