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I work on a electronic positioner transmitter 4211 at the
field.I connect my multimeter in series to get the current
output then I calibrate it to 4ma in 0% of position of the
valve and 20ma in 100% position of the valve.My problem is
in the field I get the correct output current based on my
multimeter but in the dcs they only receive 40% in a output
20ma of this positioner.Then I try to simulate in this
analog card and they receive the equivalent percent on the
value that I simulated.Is ther any possibility to reset the
zero and span of this positioner 4211 fisher.And what other
possibility I can do to fixed this.This is my email add (
landicho_randy@yahoo.com )
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Answer Posted / deepan
just check ma at dcs end
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A PLC is programmed to drive three motors A, B and C as follows : After running motor A for an hour, motor B should get ON and motor A should get OFF. And after running motor B for an hour, motor C should get ON and motor B should get OFF. And after running motor C for an hour, motor A should get ON and motor C should get OFF. (That is, a cyclic repetition with time period one hour) Now, the second condition is: If any motor gone faulty and is tripped, the consecutive motor should get ON and the faulty (tripped) motor should be eliminated from cyclic repetition. The remaining two motors should bear the cyclic repetition of one hour each. (For healthy motor take logic as high and for tripped motor take logic as low) Now, the third condition is: When motor A load(Amps) exceeds 60% of its rated load, motor B should get ON in parallel to motor A. And when both motors A & B are running in parallel, and if their load exceeds 60% of their rated load, motor C should also start in parallel to A & B. [Here the cyclic repetition is eliminated, until their loads become normal(40%)] [Take logic high(1) for load at 60% and logic low(0) for load at 40%] Now draw a flow chart or a ladder diagram to fulfill the above condition.
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