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main()
{
int i = -3,j=2,k=0,m;
m= ++i || ++j && ++k;
printf("%d%d%d",i,j,k,m);
}
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Answer Posted / nidhi yadav
here logical && has higher priority than ||. so the block
(++j&&++k)will execute first and ans of this will be (3&&1=0)
since value increment first due to preincrement operator. now
the block(++i||0)will execute as (-2||0=1) since || opertor always gives true value except(0||0=0).
thus ans will be i=-2,j=3,k=1,m=1
| Is This Answer Correct ? | 2 Yes | 7 No |
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