Answer Posted / sachin magdum

Kasi, I am not agreed with you, in your case sal will be initialized before ssn.

Debug this program and see,


class A
{
int i ;
public :
A (int _i)
{
i = _i;
}
};

class B
{
A a;
A b;
A c;

public :
B(int _a, int _b, int _c) : a(_a), c(_c), b(_b)
{}
};

int main(int argc, char* argv[])
{
B b(1,2,3);

return 0;
}

Here the initialization order is first 'a' then 'c' and then 'b' and not a, b, c.

However, if you have base class then the case is little different


class A
{
int i ;
public :
A (int _i)
{
i = _i;
}
};

class B : public A
{
A a;
A b;
A c;

public :
B(int _a, int _b, int _c, int _base) : a(_a), c(_c), b(_b), A(_base)
{}
};

int main(int argc, char* argv[])
{
B b(1,2,3,4);

return 0;
}

In this case first 'A' that is base class of B, then 'a' then 'c' then 'b' will be initialized.

If you have multiple base classes, then they will be initialized in the order of their declaration, and not in the order how they are initialized.

class A
{
int i ;
public :
A (int _i)
{
i = _i;
}
};

class C
{
int i ;
public :
C (int _i)
{
i = _i;
}
};


class B : public A, public C
{
A a;
A b;
A c;

public :
B(int _a, int _b, int _c, int _baseA, int _baseC) : a(_a), C (_baseC), c(_c), b(_b), A(_baseA)
{}
};

int main(int argc, char* argv[])
{
B b(1,2,3,4,5);

return 0;
}

In this case first 'A' then 'C' then 'a' then 'c' and then 'b' will be initialized.

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