Answer Posted / prateek

I found some good and new ways to write this programe.
Thankx to all. Well even I have also tried to make this
programe. By making use of "while loop";

#include<iostream>
#include<conio.h>

using namespace std;

void main(){

int num,n,i=0,flag=0;;
cout<<"Enter the number";
cin>>num;

n=num/2;
while(i<n)
{
++i;
if(num%i==0 && i!=1)
{
flag=1;
break;
}
else
{
flag;
}
}
if(flag)
{
cout<<"The number is not a prime number";
}
else
{
cout<<"The number is a prime number";
}

getch();


}

Plz notice, that I have divided the number by 2. Suppose
user input 42. The highest divisible value of 42 will be
its half, i.e., 21(21*2=42). So there is no need to check
the loop condition until the value of 'i' reach num. Becoz
it is for sure, that the values more than its half are not
divisible. This will increase the efficiency of the
programe.

Describe public access specifiers?

1111

---

What is the real purpose of class – to export data?

1106

---

What are the two shift operators and what are their functions?

1087

---

How is new() different from malloc()?

1120

---

What is a volatile variable in c++?

1457

---

Where do I find the current c or c++ standard documents?

1087

---

What are c++ tokens?

1052

---

Explain the virtual inheritance in c++.

1063

---

What are default parameters? How are they evaluated in c++ function?

1171

---

What is the extension of c++?

976

---

What is a c++ vector?

1040

---

What is const pointer and const reference?

1158

---

Is java based off c++?

967

---

What are containers in c++?

988

---

How can you tell what shell you are running on unix system?

1111

---