i = 2; first ++i = 3. second ++i = 4. third i++ = 5; now i =5; then,

#include<stdio.h>
int main()
{
int i=2;
int j=++i + ++i + i++;
printf("%d\n",i);
printf("%d\n",j);
}

Question Posted / kailas.s.patil

Answer Posted / kailas.s.patil

i = 2;
first ++i = 3.
second ++i = 4.
third i++ = 5;
now i =5;

then, j = 3 + 4 + 5 = 12

Is This Answer Correct ?

4 Yes

1 No

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