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#include<stdio.h>
int main()
{
int i=2;
int j=++i + ++i + i++;
printf("%d\n",i);
printf("%d\n",j);
}
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Answer Posted / ashok reddy
intially i=2
j=++i + ++i + i++;
in this statament it calculates from r-l
so j=5+4+2
and the last value of i is 5
so i=5 and j=11
is the correct answer
| Is This Answer Correct ? | 0 Yes | 0 No |
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