Answer Posted / resh

it will be 63

procedure:

let initially der are x breads

1st thief takes=x/2 +1/2 ,so remaining=x-(x/2+1/2)=x/2-1/2

2nd thief takes=1/2+1/2*(x/2-1/2)=1/2+x/4-1/4=x/4+1/4 so remain=x/2-1/2-x/4-1/4=x/4-3/4

3rd thief takes=1/2 +1/2*(x/4-3/4)=1/2+x/8-3/8=x/8+1/8 so remain=x/4-3/4-x/8-1/8=x/8-7/8

4th thief takes=1/2+1/2*(x/8-7/8)=1/2+x/16-7/16=x/16+1/16 so remain=x/8-7/8-x/16-1/16=x/16-15/16

so x/16-15/16=3

x=48+15=63(ans)

(not solved by me but got it from another site)

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